Voici comment se présente un anticorps efficace contre le coronavirus :




            
          
 O=C-NH-CH-CO-NH-CH-CO-NH-CH-CO-NH-CH-CO-NH-CH-CO-NH-CH-CO-NH-CH-CO-NH-CH-CO-NH-CH-CO-NH-CH-CO-NH-CH-CO-NH-CH-CO-NH-CH-CO-NH-CH-CO-NH-CH-CO-NH-CH-CO-NH-CH-CO-NH-CH-CO-
   |_   |        |        |        |        |        |        |	       |        |	 |	  |	   |	    |	     |	      |	       |	|	 |
   O    CH2SH    CH2      CH2      CH2SH    CH2SH    CH2SH    CH2      CH2SH	CH2	 CH2SH	  CH2SH    CH2SH    CH2SH    CH2      CH2      CH2SH	CH2	 CH2SH
		 |        |				      |  _		|  _					     |	      |			|
		 CH2      CH2				      C-O		COO					     COOH.    CH2		COOH
		 |        |  _				      |_								      |  _
		 COOH     COO				      O									      COO



-NH-CH-CO-NH-CH-CO-NH-CH-CO-NH-CH-CO-NH-CH-CO-NH-CH-CO-NH-CH-CO-NH-CH-CO-NH-CH-CO-NH-CH-CO NH2-NH-CH-NH3(+)
    |	     |	      |	       |	|	 |	  |	   |	    |	     |	      	  |
    CH2	     CH2SH    CH2SH    CH2SH	CH2SH	 CH2SH	  CH2	   CH2	    CH2	     CH2          CH2
    |							  |	   |	    |	     |	      	  |
    CH2							  COOH	   CH2	    CH2	     CH2      	  COOH
    |								   |  _	    |	     |	      
    COOH							   COO	    COO.     COOH   


Le point de l'acide aminé acide aspartique 14 est un baryon b(Z=0,A=0,charge=1symbolique,spin=3symbolique)

Le point du résidu glutamoyle 27 est un positon : e(Z=0,A=0,charge=1calligraphied,spin=2call.CH+)

Yoann Désir